20x^2-48x=36

Solution for 20x^2-48x=36 equation:

20x^2-48x=36

We move all terms to the left:

20x^2-48x-(36)=0

a = 20; b = -48; c = -36;
Δ = b2-4ac
Δ = -482-4·20·(-36)
Δ = 5184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5184}=72$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-48)-72}{2*20}=\frac{-24}{40}
=-3/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-48)+72}{2*20}=\frac{120}{40}
=3
$